|
Doc Brown's Advanced A
level theoretical chemistry revision notes
Part 8.4 Further case studies of inorganic and organic molecules comparing boiling points
and intermolecular forces
based a similar number of electrons in the molecule[Author
© Dr
Phil Brown PhD: Doc
Brown's Chemistry exam revision notes suitable
for advanced A level chemistry students studying pre–university/college advanced level
theoretical–physical chemistry courses:
boiling point
comparisons [page updated May 2nd 2026 *]
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Sub-index for this page in the context of intermolecular bonding
Further comparisons of the boiling points of
some series of inorganic and organic compounds and relating their
boiling points to the intermolecular forces (intermolecular bonding)
involved.
In this
section 8.4 I am assuming you are familiar with the different types of
intermolecular bonding, particularly:
Read first
Summary of Van der
Waals forces and introduction to intermolecular forces
Instantaneous
dipole – induced dipole interactions (London forces or dispersive
forces)
Permanent dipole
– permanent dipole interactions (Keesom forces/orientation forces)
and
Hydrogen bonding
intermolecular forces
otherwise this
page might prove more difficult than is necessary!
8.4.1 Case study 1.
Comparing selected physical properties of 10
electron inorganic molecules (and methane) of molecular mass 16 to
20
8.4.2 Case study 2.
Comparing
selected physical properties some inorganic and organic molecules with 18 electrons and molecular mass 32-40
8.4.3 Case study 3.
Comparing
the physical properties of selected organic molecules with totals of 24-26 electrons
and molecular mass 46 to 50.5
8.4.4 Case study 4.
Comparing
selected organic molecules with totals of 56-58 electrons and molecular
mass ~100-106
8.4.5
Some after thoughts
8.4.1
(Case study 1)
Comparing selected physical properties of 10 electron inorganic
molecules (and methane) of molecular mass 16 to 20
Some extra
case studies on boiling point, intermolecular forces and electrons in a
molecule
Note 8 organic molecules are discussed
in detail in section 8.2.6
Much of the
data on this page was obtained from the NIST website
https://webbook.nist.gov/
|
Table 8.4.1 Comparing 10
electron species – noble gas, some very small organic/inorganic
molecules with 10 electrons, relative molecular mass 16-20 |
|
MOLECULE |
formula |
Mr |
electrons |
Bpt K/oC |
ΔHvap/kJmol–1 |
Dipole
moment/D |
Relative
polarizability |
|
neon |
Ne |
20 |
10 |
27K/–246oC |
1.8 |
0.00 |
0.38 |
|
methane |
CH4 |
16 |
10 |
109K/–164oC |
8.2 |
0.00 |
2.45 |
|
ammonia |
NH3 |
17 |
10 |
240K/–33oC |
23.4 |
1.48 |
2.10 |
|
hydrogen fluoride |
HF |
20 |
10 |
293K/20oC |
31.2 |
1.91 |
0.80 |
|
water |
H2O |
18 |
10 |
373K/100oC |
41.1 |
1.84 |
1.50 |
-
Series 8.4.1
Comparing 10 electron species
- This series offers quite a range
of boiling points!
- Remember
that instantaneous dipole - induced dipole intermolecular force
attractions occur between ALL molecules, but the total
intermolecular bonding may include contributions from permanent
dipole - permanent dipole attractions from molecules having
polar bonds.
- Neon, Ne (can consider as
a monatomic molecule')
- The most compact 10 electron
system you can have, but not a good baseline for further
discussion because it is evident from the following four
molecules, as soon as
- Even in the case of
helium,
lowest boiling point of any substance, you still can get
transient dipoles because of the random behaviour of the
electrons ...
-
attractions
- It would be a similar diagram
for neon. consider polarizability
-
Methane, CH4
- Methane is a highly symmetrical
molecule with no significant bond polarity.
- Clearly, in comparing
methane with water, ammonia or hydrogen fluoride, which all
exhibit hydrogen bonding, the non–polar nature of methane
gives rise to considerably weaker intermolecular forces,
namely instantaneous dipole - induced dipole attractions.
- In principle, the
intermolecular bonding is no different than for neon.
-
Ammonia, NH3
- Instantaneous
dipole - induced dipole intermolecular force plus permanent
dipole - permanent dipole forces and hydrogen bonding
increasing the boiling point considerably.
- ....δ–:N–Hδ+llllδ–:N–Hδ+.... etc.
- The hydrogen bonding in the
highly polar molecules of ammonia, hydrogen fluoride and water
results in a clear 'extra' increase in the value of the molar
enthalpy of vaporisation compared to non-polar methane and neon
i.e. more kinetic energy is needed to separate and vaporise the
molecules in the liquid.
-
Hydrogen fluoride, HF
- Instantaneous
dipole - induced dipole intermolecular force, plus permanent
dipole - permanent dipole intermolecular forces.
- Hydrogen fluoride displays
hydrogen bonding and a greatly increased boiling point would be
expected compared to methane.
- It can only form one hydrogen
bond per molecule (*) and so the boiling point is considerably
raised compared to methane BUT not as much as for water.
- (*) It does form moderately
stable zig–zag
'polymer' molecules in the gaseous phase just above its boiling
point, which is probably why it has a higher boiling point than
hydrogen bonded ammonia.
- ....δ–:F–Hδ+
llll
δ–:F–Hδ+.... etc.
-
More on hydrogen bonding
-
Water, H2O
8.4.2 (Case
study 2)
Comparing
selected physical properties some inorganic and organic molecules with 18 electrons and molecular mass 32-40
|
Table 8.4.2 Comparing
18
electron species – noble gas, small organic/inorganic
molecules |
|
MOLECULE |
formula |
Mr |
electrons |
Bpt K/oC |
ΔHvap/kJmol–1 |
Dipole
moment/D |
Relative polarizability |
|
argon |
Ar |
40 |
18 |
87K/–186oC |
6.53 |
0.00 |
1.66 |
|
fluorine |
F2 |
38 |
18 |
85K/–188oC |
3.16 |
0.00 |
1.16 |
|
ethane |
CH3CH3 |
30 |
18 |
184K/–89oC |
14.7 |
0.00 |
4.23 |
|
fluoromethane |
CH3F |
34 |
18 |
185K/–88oC |
16.4 |
1.86 |
2.54 |
|
phosphine |
PH3 |
34 |
18 |
185K/–88oC |
14.6 |
0.55 |
4.24 |
|
hydrogen sulphide |
H2S |
34 |
18 |
212K/–61oC |
18.7 |
0.92 |
3.63 |
|
hydrogen chloride |
HCl |
36.5 |
18 |
188K/–85oC |
16.2 |
1.05 |
2.52 |
|
methanol |
CH3OH |
32 |
18 |
338K/65oC |
43.5 |
1.71 |
3.21 |
|
hydrazine |
H2NNH2 |
32 |
18 |
386K/113oC |
40.4 |
0.00 |
3.46 |
-
Series 8.4.2 Comparing 18
electron species
-
argon, Ar
(can consider as a monatomic molecule')
- Only the
instantaneous dipole - induced dipole intermolecular force
(London dispersion force) operates between argon atoms.
- Argon can be liquefied, like all
the noble gases because the random behaviour of electrons in the
orbitals of the electron clouds there is never perfectly
symmetrical distribution of electrical charge so transient
dipole – induced dipole forces only.
- In fact down
Group 0/18 the boiling points steadily increase down the group with increasing
numbers of
electrons and the greater polarizability of the
atom increasing the instantaneous dipole – induced dipole forces.
- i.e. 86Rn >
54Xe > 36Kr > 18Ar > 10Ne
- (pre–subscript = proton/atomic number = electrons)
-
fluorine, F2
- Only the
instantaneous dipole - induced dipole intermolecular force
(London dispersion force) operates between
fluorine molecules.
- Its boiling point is very similar
argon despite the greater spread of electron charge over both atoms
of the diatomic molecule.
- With the highest electronegativity,
perhaps the electrons are as compact as in argon?
-
ethane, CH3CH3
- Only the
instantaneous dipole - induced dipole intermolecular force
(London dispersion force) operates between
ethane molecules.
- Despite having the same number
of electrons as argon, the boiling point is 97o
higher.
- Ethane can act as a baseline for
the rest of this series since the electrons are more spread out
and it is a totally non–polar molecule with only
instantaneous dipole – induced dipole forces operating.
-
fluoromethane, CH3F
- Instantaneous
dipole - induced dipole intermolecular force (London dispersion
force) plus permanent dipole - permanent dipole intermolecular
force (Keesom orientation force) operate between fluoromethane
molecules.
- Despite the fact that the C–F bond
is quite polar, this permanent dipole seems to contribute virtually
nothing to increasing the intermolecular forces and fluoromethane
has similar boiling point to ethane (in fact it is actually less!).
-
phosphine, PH3
- Only the
instantaneous dipole - induced dipole intermolecular force
(London dispersion force) operates between
ethane molecules.
- The electronegativity of P is
2.1, the same as hydrogen, therefore PH3 is a
non–polar molecule with a boiling point similar to the equally
non–polar ethane.
-
hydrogen sulphide, H2S
- The electronegativity of S is
2.5 so the S–H bond is slightly polar and there is a small
increase in boiling point compared to the non–polar ethane and
phosphine and has a higher boiling point than hydrogen chloride
with its more polar bond. This may be due to the fact that there
are two S–H bonds and the electrons are more spread out and more
polarizable?
- Total intermolecular force =
(instantaneous dipole – induced dipole) + (permanent dipole
–
permanent dipole including hydrogen bonding) + (permanent dipole
–
induced dipole)
-
Hydrogen chloride, HCl
- Similarly, in the case of the
obviously polar hydrogen chloride molecule, the presence of the
permanent dipole has virtually no effect on the boiling point
compared to what you might expect for an 18 electron non–polar
molecule. This suggests that the intermolecular forces operating in
the first three molecules all have their origin in the instantaneous
dipole – induced dipole forces, despite the picture below!
-
attractions
seem to make little difference to the bpt!
- Total intermolecular force =
(88% instantaneous dipole – induced dipole) + (7.5% permanent dipole
–
permanent dipole including hydrogen bonding) + (4.5% permanent dipole
–
induced dipole)
-
methanol, CH3OH
- Instantaneous dipole - induced
dipole intermolecular force (London dispersion force) and
permanent dipole - permanent dipole intermolecular force (Keesom
orientation force) including hydrogen bonding.
- Since methanol exhibits hydrogen bonding, so the
extra intermolecular force increases the boiling point considerably, perhaps by nearly
doubling it ...
- so for CH3–δ–O–Hδ+
we have the
δ–O–Hδ+llllδ–:O–Hδ+
situation ...
- ... and the permanent dipole –
permanent dipole attractions of the hydrogen bonding
play a very significant % of the intermolecular forces.
- Total intermolecular force =
(61.3% instantaneous dipole – induced dipole) + (30.3% perm. dipole
–
permanent dipole including hydrogen bonding) + (8.4% permanent dipole
–
induced dipole)
- The hydrogen bonding in the
highly polar molecules of methanol and hydrazine, again, results
in a clear 'extra' increase in the value of the molar enthalpy
of vaporisation compared to non-polar or weakly polar molecules
i.e. more kinetic energy is needed to separate and vaporise
these two molecules.
-
More on hydrogen bonding
-
hydrazine, N2H4
or H2N–NH2
- Hydrazine's boiling
point is another 48oC higher than the hydrogen bonded methanol and with good reason,
there are two sites for hydrogen bonding on the same small molecule
(x–ref water). Both –NH2 groups have the highly N–H
bond giving rise to the permanent dipole – permanent dipole
attractions of hydrogen bonding.
- ...H–N:δ–llllδ+H2NH–NH2δ+llll
δ–:N–H...
8.4.3 (Case
study 3)
Comparing
the physical properties of selected organic molecules with totals of 24-26 electrons
and molecular mass 46 to 50.5
|
Table 8.4.3 Comparing
organic molecules
24–26
electron species, molecular mass ~46-50
They are all linear organic molecules of 3 C, O
or N atoms |
|
MOLECULE |
formula |
Mr |
electrons |
Boiling point |
ΔHvap kJmol–1 |
Dipole moment/D |
Relative polarizability |
|
propane |
CH3CH2CH3 |
46 |
26 |
231K/–42oC |
19 |
0.00 |
5.92 |
|
methoxymethane |
CH3OCH3 |
46 |
26 |
248K/–25oC |
21 |
1.30 |
5.16 |
|
chloromethane |
CH3Cl |
50.5 |
26 |
249K/–24oC |
21 |
1.87 |
4.42 |
|
ethanal |
CH3CHO |
44 |
24 |
294K/21oC |
26 |
2.50 |
4.28 |
|
ethanol |
CH3CH2OH |
46 |
26 |
351K/78oC |
42 |
1.70 |
5.11 |
|
methanoic acid |
HCOOH |
46 |
24 |
374K/101oC |
45 |
1.52 |
3.32 |
|
methanamide |
HCONH2 |
45 |
24 |
466K/193oC
(decomposes) |
65 |
3.71 |
4.08 |
-
Series 8.4.3 Comparing
24–26
electron species to add polarizability
-
(slightly larger linear organic
molecules of 3 C, O or N atoms)
-
propane,
CH3CH2CH3
-
Propane can act as a baseline for
this series since it is a totally non–polar molecule with only
instantaneous dipole – induced dipole forces operating.
-
Total intermolecular force =
(100% instantaneous dipole – induced dipole)
-
methoxymethane,
CH3OCH3
-
The presence of the
C–O–C does seem to raise the boiling point a bit, despite the fact
the two C–O polar bonds tend to cancel each other out, resulting in
a relatively non–polar molecule.
-
Total intermolecular force =
(instantaneous dipole – induced dipole) + (permanent dipole
–
permanent dipole) + (permanent dipole –
induced dipole)
-
chloromethane,
CH3Cl
-
Despite the single polar C–Cl bond this
doesn't seem to increase the boiling point much above what get for
the ether methoxymethane.
-
Total intermolecular force =
(instantaneous dipole – induced dipole) + (permanent dipole
–
permanent dipole) + (permanent dipole –
induced dipole)
-
ethanal,
CH3CHO
-
However the polar C=O bond in
ethanal does increase the intermolecular forces an extra amount to
raise the boiling point ~30–60o above what expected for a
non–polar molecule.
-
Total intermolecular force =
(instantaneous dipole – induced dipole) + (permanent dipole –
permanent dipole) + (permanent dipole –
induced dipole)
-
ethanol,
CH3CH2OH
-
Here there is an
even greater increase in boiling point due to hydrogen bonding.
-
Total intermolecular force =
(instantaneous dipole – induced dipole) + (permanent dipole –
permanent dipole including hydrogen bonding) + (permanent dipole
–
induced dipole)
-
A theoretical figure quoted for
2–methylpropan–2–ol (tert–butanol), a similar molecule, for the
total intermolecular force was: (67.2% instantaneous dipole
–
induced dipole) + (23.1% permanent dipole – induced dipole including H
bonding) + (9.7% permanent dipole – induced dipole)
-
Note that the hydrogen
bonding only contributes ~1/4 of the total
intermolecular force (Van der Waals forces) but this is sufficient
to raise the boiling point significantly above that of a non–polar
molecule of similar molecular mass (particularly if similar number
of electrons).
-
However in the case of
ethanol you would expect a greater contribution from the
permanent dipole – permanent dipole interactions (including the
hydrogen bonding).
-
The quotation for
methanol is: (61.3% instantaneous dipole –
induced dipole) + (30.3% permanent dipole – induced dipole including H
bonding) + (8.4% permanent dipole – induced dipole)
-
The intermolecular forces for ethanol
are approximately: (42.6% instantaneous dipole –
induced dipole) + (~47.6% permanent dipole – induced dipole including H
bonding) + (9.7% permanent dipole – induced dipole)
-
Textbooks tend to
indicate that hydrogen bonding is the predominant intermolecular
force in molecules such as alcohols, but this is very rarely the
case (only a few other molecules like,
water,
methanol
(methyl alcohol),
methanamide (formamide)
and
ethanamide (acetamide) really, for
the vast majority of molecules the predominant intermolecular
attraction is the instantaneous dipole – induced dipole interaction
(the weakest of the forces!).
-
The hydrogen bonding
in the highly polar molecules of ethanol, methanoic acid and
methanamide, not surprisingly, results in a clear 'extra' increase
in the value of the molar enthalpy of vaporisation compared to
non-polar or weakly polar molecules i.e. more kinetic energy is
needed to separate and vaporise these two molecules compared to less
polar molecules.
-
methanoic acid,
HCOOH
-
For carboxylic acids the two
permanent dipoles C=O and O–H, and both sites available for hydrogen
bonding means the boiling point is raised even further and linear or
cyclic dimers formed. (see ethanoic acid)
-
Here there is an
even greater increase in boiling point due to hydrogen bonding.
-
Total intermolecular force =
(instantaneous dipole – induced dipole) + (permanent dipole –
permanent dipole including hydrogen bonding) + (permanent dipole
–
induced dipole)
-
I would estimate that
70–80% of the intermolecular attractive force in methanoic acid
comes from the permanent dipole – permanent dipole attractions
including hydrogen bonding.
-
methanamide,
HCONH2
-
Like carboxylic acids,
amides have two
permanent dipoles, in this case C=O and N–H, and both sites available for hydrogen
bonding means the boiling point is raised even further. (see ethanoic acid)
-
So again there is an
even greater increase in boiling point due to hydrogen bonding.
-
Total intermolecular force =
(3.2% instantaneous dipole – induced dipole) + (93.3%
permanent dipole – permanent dipole including hydrogen bonding) + (3.5% permanent dipole
–
induced dipole)
-
Its interesting here
that the boiling point of methanamide is raised another ~100o
compared to the hydrogen bonded methanoic acid. I'm not quite
sure why? Can more hydrogen bonds be formed? Are much larger
polymeric species formed in liquid methanamide? Not sure
on this one but
ethanamide behaves in the
same way with respect to ethanoic acid!
8.4.4
Case study 4.
Comparing
some organic molecules with totals of 56-58 electrons and molecular
mass ~100-106
|
Table 8.4.4 Comparing
56–58
electron species –
larger linear organic molecules with 7 C/O/N atoms |
|
MOLECULE |
formula |
Mr |
electrons |
Boiling point |
ΔHvap
in kJmol–1 |
Dipole moment/D |
|
heptane |
CH3CH2CH2CH2CH2CH2CH3 |
100 |
58 |
371K/98oC |
36.6 |
0.00 |
|
1-methoxypentane |
CH3CH2CH2CH2CH2OCH3 |
102 |
58 |
372K/99oC |
36.9 |
1.51 |
|
1–fluorohexane |
CH3CH2CH2CH2CH2CH2F |
104 |
58 |
365K/92oC |
36.9 |
~2 ? |
|
1–chloropentane |
CH3CH2CH2CH2CH2Cl |
106.5 |
58 |
381K/108oC |
38.3 |
2.16 |
|
1–methylethyl ethanoate |
CH3COOCH(CH3)2 |
102 |
56 |
366K/93oC |
33.0 |
1.75 |
|
methyl butanoate |
CH3CH2CH2COOCH3 |
102 |
56 |
375K/102oC |
41.1 |
1.72 |
|
ethyl propanoate |
CH3CH2COOCH2CH3 |
102 |
56 |
372K/99oC |
36.7 |
1.80 |
|
propyl ethanoate |
CH3COOCH2CH2CH3 |
102 |
56 |
375K/102oC |
39.1 |
1.79 |
|
butyl methanoate |
HCOOCH2CH2CH2CH3 |
102 |
56 |
380K/107oC |
39.3 |
2.03 |
|
hexanal |
CH3CH2CH2CH2CH2CHO |
100 |
56 |
402K/129oC |
40.8 |
2.29 |
|
hexan–2–one |
CH3COCH2CH2CH2CH3 |
100 |
56 |
400K/127oC |
43.0 |
2.69 |
|
hexan–1–ol |
CH3CH2CH2CH2CH2CH2OH |
102 |
58 |
429K/156oC |
51.4 |
1.60 |
|
pentanoic acid |
CH3CH2CH2CH2COOH |
102 |
56 |
459K/186oC |
58.0 |
1.61 |
|
pentanamide |
CH3CH2CH2CH2CONH2 |
101 |
56 |
498K/225oC |
71.4 |
3.80 |
-
Series Table 8.4.4 Comparing 56–58
electron species – larger linear organic
molecules
-
heptane,
CH3CH2CH2CH2CH2CH2CH3
polarizability
-
1–fluorohexane,
CH3CH2CH2CH2CH2CH2F
-
1–chloropentane,
CH3CH2CH2CH2CH2Cl
-
hexanal,
CH3CH2CH2CH2CH2CHO
-
hexan–2–one,
CH3COCH2CH2CH2CH3
-
hexan–1–ol,
CH3CH2CH2CH2CH2CH2OH
-
pentanoic acid,
CH3CH2CH2CH2COOH
- Note that, even in the last two
molecules, most of the intermolecular attractive force will still
originate from the temporary dipole – induced dipole interactions.
The base–line' is about 370K for heptane, so the permanent dipoles/H
bonding have increased the boiling point of pentanoic acid by about
23%.
8.4.5 Some after thoughts!
- What we can explain by using
permanent dipole arguments, is why a boiling point of a polar
molecule is raised above
an expected value for a non–polar molecule with no permanent dipole.
- BUT, remember that for most molecules the majority of the
intermolecular force is due to transient dipole – induced dipole
attraction and the lesser difference in electronegativity of the two
atoms of the covalent bond decreasing
the polarity of the
- What is not easy, is to explain is why
the C–F, C–Cl and H–Cl polar bonds seem to have no real effect on
the intermolecular forces compared to what you expect for a
non–polar molecule?
- Again it should be emphasised that
permanent dipoles like
δ+C=Oδ– and
δ–O–Hδ+ obviously contribute an extra
component to the intermolecular forces.
- BUT it should ALSO be emphasised
that if these dipoles are in these 'bigger' molecules most of the intermolecular force
still originates from transient dipole – induced dipole attraction if the
other bonds are relatively non–polar.
Some learning objectives for
comparing
intermolecular bonding between different inorganic and organic molecules
From a given molecular
structure, be able to recognise the types of intermolecular bonding
that can occur between molecules.
Be able to argue why
e.g. boiling points and enthalpies of vaporisation will increase
with increase in the strength of the intermolecular bonding.
Be able to compare and
explain similarities or differences between molecules of similar
size, particularly in having the same, or very similar, numbers of
electrons in terms of their intermolecular bonding, boiling point
and enthalpy of vaporisation.
WHAT NEXT?
INDEX for Part 8.
Phase equilibria–vapour
pressure, boiling point and intermolecular forces
Index of ALL my chemical equilibrium
context revision notes
Part 8 sub–index:
8.1 Vapour pressure, nature, origin and examples
explained * 8.2.1
Introduction to the types of intermolecular forces
and examples explained (index) * 8.2.2 Detailed comparative discussion of boiling points of 8 organic molecule
of similar molecular mass * 8.3
Boiling point plots of six
organic
homologous series - graphs and explanation * 8.4
Other case studies of
boiling points related to intermolecular forces * 8.5
Steam
distillation – theory and practice * Evidence and theory
for hydrogen bonding in simple covalent hydride *
8.7 Solubility of covalent compounds, miscible and
immiscible liquids
Advanced Equilibrium Chemistry Notes Part 1. Equilibrium,
Le Chatelier's Principle–rules * Part 2. Kc and Kp equilibrium expressions and
calculations * Part 3.
Equilibrium and industrial processes * Part 4.
Partition,
solubility product and ion–exchange * Part 5.
pH, weak–strong acid–base theory and
calculations * Part 6. Salt hydrolysis,
Acid–base titrations–indicators, pH curves and buffers *
Part 7.
Redox equilibria, half–cell electrode potentials,
electrolysis and electrochemical series
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