SITEMAP   School Physics Notes: Turning Forces 5.2 Simple moment calculations

UK GCSE level age ~14-16 ~US grades 9-10 Scroll down, take time to study content or follow links

5 Turning forces: 5.2 Some simple examples of moment calculations

Doc Brown's Physics exam study revision notes

This page contains online questions only. Jot down your answers and check them against the worked out answers at the end of the page

5.2 Some simple moment calculations using the moment formula

Q1

Calculate the moment if a force of 5.0 N is applied to a spanner 15 cm long.

Worked out ANSWERS

Q2 A force of 20 N is applied to a door causing a moment of 5 Nm.

Calculate the distance in cm from the hinge axle to the point on the door where the force was applied.

Worked out ANSWERS

Q3 What force must applied to a 30 cm long spanner to generate a moment of 6.0 Nm?

Keywords, phrases and learning objectives for turning forces

Know the formula for calculating a moment and be able to do simple moment calculations.

WHAT NEXT?

BIG website, using the [SEARCH BOX] below, maybe quicker than navigating the many sub-indexes

for UK KS3 science students aged ~12-14, ~US grades 6-8

ChemistryPhysics for UK GCSE level students aged ~14-16, ~US grades 9-10

for pre-university age ~16-18 ~US grades 11-12, K12 Honors

Use your mobile phone in 'landscape' mode?

SITEMAP Website content © Dr Phil Brown 2000+. All copyrights reserved on Doc Brown's physics revision notes, images, quizzes, worksheets etc. Copying of website material is NOT permitted. Exam revision summaries and references to GCSE science course specifications are unofficial.

Using SEARCH some initial results may be ad links you can ignore - look for docbrown

Worked out ANSWERS to the moment calculations

Q1

Calculate the moment if a force of 5.0 N is applied to a spanner 15 cm long.

F = 5, d = 15/100 = 0.15 m

moment M = F x d = 5 x 0.15 = 0.75 Nm

Q2 A force of 20 N is applied to a door causing a moment of 5 Nm.

Calculate the distance in cm from the hinge axle to the point on the door where the force was applied.

moment M = F x d, so d = M/F = 5/20 = 0.25 m,

therefore d = 0.25 x 100 = 25 cm

Q3 What force must applied to a 30 cm long spanner to generate a moment of 6.0 Nm?

moment M = F x d, so F = M/d, d = 30 cm = 30/100 = 0.30 m

F = M/d = 6.0/0.30 = 20 N

 @import url(https://www.google.co.uk/cse/api/branding.css); ENTER specific physics words or courses e.g. topic, module, exam board, formula, concept, equation, 'phrase', homework question! anything of physics interest!  This is a very comprehensive Google generated search of my website

TOP OF PAGE