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School-college Physics Notes: Electricity 3.7 Division of p.d. in a series circuit

Electricity Section 3: Three resistors in series.

3. 7 How the total potential difference is split between resistances in series

[Author © Dr WP Brown PhD: Doc Brown's physics exam revision notes suitable for students of UK IGCSE & GCSE level physics courses, ~ US grades 9-10 physics, electricity page updated Feb 8th 2026]

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INDEX for electricity section 3 notes on current, voltage, resistance, energy & charge transfer in circuits


3.7 A little more on potential difference - effect of two resistors in series - explaining and verifying by calculation, how the potential difference is split between resistances in series

Explaining and verifying by calculation, how the potential difference (p.d.) is split (divided, shared) between resistances in series i.e. the effect of two (or more) resistors in series

circuit diagram showing how a p.d. is split between two resistors wired in series

The circuit 41 shows two resistors wired in series, so how is the total p.d. divided or shared between the two resistance wired in series.

This circuit can be used to investigate and confirm the correctness of the following theoretical calculations.

On the right is shown what happens to the p.d. going clockwise around the circuit (direction of convention current).

 

The potential store of the battery raises the potential difference of the charge to 12.0 V.

The total resistance = 10.0 + 5.0 = 15.0 Ω (you can add resistors up if wired in series)

Therefore the current flowing round all of this series circuit

= I = V / Rtotal = 12.0 / 15.0 = 0.80 A

 

As the charge passes through the 1st resistor R1, it loses energy and the p.d. falls by 8 V to a p.d. of 4 V.

Calculation to confirm this:  V1 = I x R1 = 0.80 x 10.0 = 8.0 V

 

As the charge passes through the 2nd resistor R1, it loses energy again and the p.d. falls by 4 V to a p.d. of 0 V.

Calculation to confirm this:  V2 = I x R2 = 0.80 x 5.0 = 4.0 V

 

As long as there is a complete circuit, the process repeats itself through any number of resistors.

What is clear is the total p.d. for the circuit is split into a p.d. ratio identical to the resistor ratio.

V1 : V2 is the same ratio as R1 : R2

 

You can also say that since E = QV, twice as much energy is released by resistor R1 (p.d. 8 V) than R2 (p.d. 4 V) for the same total current, the same total charge transferred, but the lower the p.d. the less potential energy carried by the charge.

 

INDEX of electricity section 3 notes on current, voltage, resistance, energy & charge transfer in circuits including Ohm's Law investigations


Key points about electric circuits in physics courses - fall in p.d. across resistors in series

Information sources for Doc Brown's key points: IGCSE-GCSE physics are based on textbooks & syllabus-specifications for students taking the UK AQA, Edexcel, OCR 21st Century Science, OCR Gateway science suite, WJEC, CCEA and CIE GCSE physics 9-1 level science examinations.

Keywords, phrases and learning objectives for electricity topics involving resistances in series

Be able to explain and verifying by calculation (and experiment), how potential difference is split and shared divided between resistances in series.

Be able to describe the effect of two resistors in series on the p.d. across these resistors wired in series.


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