Advanced Organic Chemistry: Mass spectrum of bromoethane CH3CH2Br

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Interpreting the mass spectrum of bromoethane

[Author ©  Dr Phil Brown PhD: Doc Brown's advanced level organic chemistry exam revision notes suitable for students of UK A level chemistry courses & US K12 grade 11, grade 12 & AP honors chemistry courses: Molecular spectroscopy of bromoethane [spectra updated Mar 19th 2026 *]

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Introductory note on the mass spectrum of bromoethane

Students and teachers please note my explanation of the mass spectrum of bromoethane is designed for advanced, but pre-university, chemistry courses.

If M represents the bromoethane molecule, the initial ionisation to give the molecular ion is:

M(g) + high KE e-  ==> [M]+(g) + 2e- and for fragmentation equations assume [M]+ is the start of the processes and all species are in a gaseous state.

I've not usually shown an unpaired electron on e.g. an ion or a non-ionised alkyl radical R e.g.

[M]+ ==> [X]+  +  R, but you should be aware this is a more accurate depiction of some processes.

I've used simplified equations to show how some of the ions that might be formed in the fragmentation pattern for the mass spectrum of bromoethane and only the formation of singly charged positive are considered for the mass spectrum of bromoethane.

I've included a stick diagram and table of m/z ions for the mass spectrum of bromoethane and doing the mass spectrum analysis under standard conditions, databases can be compiled based on complex fingerprint patterns, often involving the relative intensities of many fragment ions, and used to identify compounds including bromoethane.

In selected cases, where two different fragment ions have the same integer m/z value, I've pointed out that modern mass spectrometers can measure relative ion mass to four decimal places. So, using accurate isotopic masses, I've calculated the accurate ion masses, BUT strictly speaking, 0.0005 should be deducted for singly charged ions to account for the loss of the electron in their formation. I have NOT done this for bromoethane, but the mass spectrometer software does!

C2H5Br CH3CH2Br mass spectrum of bromoethane fragmentation pattern of m/z m/e ions for analysis and identification of bromoethane ethyl bromide image diagram doc brown's advanced organic chemistry revision notes 

Bromoethane  (c) doc b  (c) doc b  (c) doc b  (c) doc b  (c) doc b 

The molecular structure and naming of haloalkanes

Interpreting the fragmentation pattern of the mass spectrum of bromoethane

[M]+ is the molecular ion peak with an m/z of 108 (M peak) and 110 (M+2 peak) corresponding to the ions  [C2H579Br]+ and [C2H581Br]+ the original bromoethane molecule minus an electron, [CH3CH2Br]+.

There are two molecular ion peaks because bromine as two isotopes, 50.5% 79Br and 50.5% 81Br.

One peak is slightly shorter for the molecular ion with the slightly less abundant heavier bromine isotope.

Their average relative mass is ~80, so the relative molecular mass for bromoethane is ~109.

However, this means any fragment carrying a bromine atom should show up as twin peaks, two mass units apart and approximately of equal height (intensities), though intensity of ions with the heavier bromine isotope are slightly smaller..

The small M+1 and M+2 peaks at m/z 109 and 111, corresponds to an ionised bromoethane molecule with one 13C atom in it

i.e. an ionised bromoethane molecule of formula [13C12CH579Br]+ (M ion peak) and  [13C12CH581Br]+ (M+2 ion peak), because the latter has the slightly less abundant heavier bromine isotope.

Carbon-13 only accounts for ~1% of all carbon atoms (12C ~99%), but the more carbon atoms in the molecule, the greater the probability of observing these 13C peaks.

Bromoethane has 2 carbon atoms, so on average, ~1 in 50 molecules will contain a 13C atom.

They seem to show up clearly because the parent molecular ions (m/z 108 and 110) are relatively stable, their intensities are second only to the base ion peak of m/z 29.

The most abundant ion of the molecule under mass spectrometry investigation (bromoethane) is usually given an arbitrary value of 100, called the base ion peak, and all other abundances ('intensities') are measured against it.

The base ion peak in the mass spectrum of bromoethane is the m/z 29 ion [C2H5]+

Identifying the species giving the most prominent peaks (apart from M) in the fragmentation pattern of bromoethane.

Unless otherwise indicated, assume the carbon atoms in the bromoethane molecule are the 12C isotope.

m/z value of [fragment]+ 111 110 109 108 95
[molecular fragment]+ [13C12CH581Br]+ [C2H581Br]+ [13C12CH579Br]+ [C2H579Br]+ [CH281Br]+
m/z value of [fragment]+ 93 81 79 29 28 27 26 25
[molecular fragment]+ [CH279Br]+ [81Br]+ [79Br]+ [C2H5]+ [C2H4]+ [C2H3]+ [C2H2]+ [C2H]+

The small peaks at m/z 80 and 82 are due to the ionised HBr molecules formed by elimination from the parent molecular ion of bromoethane i.e. [H79Br]+  and [H81Br]

Analysing and explaining the principal ions in the fragmentation pattern of the mass spectrum of bromoethane

PLEASE NOTE I have found it difficult to find 'authentic' equations to explain mass spectra fragmentation patterns and it is complex chemistry! I've identified the formulae of the ionised fragments on the mass spectrum diagram, but the equations are from the internet or my conjecture as to how the ions might be formed - please take care in using the information, especially for assignments at university or pre-university level.

Atomic masses: C = 12 (~1% 13);  H = 1; Br = 79 and 81

Bond enthalpies kJ/mol: C-C = 348;  C-H = 412;  C-Br = 276;

Possible equations to explain the most abundant ion peaks from the fragmentation of ionised bromoethane molecules.

Formation of m/z 93 and 95 ions:

[CH3CH2Br]+  ===>  [CH2Br]+  +  CH3

C-C bond scission with mass loss of methyl group,

mass changes 108 - 15 = 93, 110 - 15 = 95

(bromine can be 79Br or 81Br, see data table of ionised fragments)

Where R is alkyl, the double RBr peaks of roughly 1 : 1 abundance ratio are characteristic of organo-bromine compounds (one m/z ion peak is slightly shorter than the other, technically 50.7 : 49.3).

Formation of m/z 79 to 81 ions:

[CH3CH2Br]+  ===>  [79Br]+  or  [81Br]  +  CH2CH3

C-Br bond scission with mass loss of ethyl group,

mass changes 108 - 29 = 79, 110 - 29 = 81

m/z 80 and 82 ions could be formed by elimination of HBr, leaving ethene

[CH3CH2Br]+  ===>  [H79Br]+  or  [H81Br]  +  CH2=CH2

Alternatively the ethene fragment could be ionised to give the m/z 28 ion [C2H4]+

[CH3CH2Br]+  ===>  [CH2=CH2]+  +  HBr

(see also below for m/z 29 ion - H atom)

Formation of m/z 29 ion:

[CH3CH2Br]+  ===>  [CH3CH2]+  +  Br

C-Br bond scission and the ethyl fragment carries the positive charge.

This is breaking the weakest bond in the bromoethane molecule.

The m/z 29 ion is the base peak ion, the most abundant and 'stable' ion fragment.

The ethyl cation loses successive protons to generate m/z ions of masses 28 => 27 => 26 => 25 (see data table of fragment ions).


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The infrared spectrum of bromoethane

The H-1 NMR spectrum of bromoethane

The C-13 NMR spectrum of bromoethane

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