Advanced Organic Chemistry: Mass spectrum of 2-methylbut-1-ene CH3CH2C(CH3)=CH2

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Interpreting the mass spectrum of 2-methylbut-1-ene

[Author ©  Dr Phil Brown PhD: Doc Brown's advanced level organic chemistry exam revision notes suitable for students of UK A level chemistry courses & US K12 grade 11, grade 12 and AP honors chemistry courses: Molecular spectrometry - analysing the mass spectrum of 2-methylbut-1-ene  [spectra page updated Mar 13th 2026 *]

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Introductory note on the mass spectrum of 2-methylbut-1-ene (2-methyl-1-butene)

Students and teachers please note my explanation of the mass spectrum of 2-methylbut-1-ene is designed for advanced, but pre-university, chemistry courses.

If M represents the 2-methylbut-1-ene molecule, the initial ionisation to give the molecular ion is:

M(g) + high KE e-  ==> [M]+(g) + 2e- and for fragmentation equations assume [M]+ is the start of the processes and all species are in a gaseous state.

I've not usually shown an unpaired electron on e.g. an ion or a non-ionised alkyl radical R e.g.

[M]+ ==> [X]+  +  R, but you should be aware this is a more accurate depiction of some processes.

I've used simplified equations to show how some of the ions that might be formed in the fragmentation pattern for the mass spectrum of 2-methylbut-1-ene and only the formation of singly charged positive are considered for the mass spectrum of 2-methylbut-1-ene.

I've included a stick diagram and table of m/z ions for the mass spectrum of 2-methylbut-1-ene and doing the mass spectrum analysis under standard conditions, databases can be compiled based on complex fingerprint patterns, often involving the relative intensities of many fragment ions, and used to identify compounds including 2-methylbut-1-ene.

In selected cases, where two different fragment ions have the same integer m/z value, I've pointed out that modern mass spectrometers can measure relative ion mass to four decimal places. So, using accurate isotopic masses, I've calculated the accurate ion masses, BUT strictly speaking, 0.0005 should be deducted for singly charged ions to account for the loss of the electron in their formation. I have NOT done this, but the mass spectrometer software does!

mass spectrum of 2-methylbut-1-ene fragmentation pattern of m/z m/e ions for analysis and identification of 2-methylbut-1-ene image diagram 2-methyl-1-butene doc brown's advanced organic chemistry revision notes 

2-methylbut-1-ene C5H10, alkenes structure and naming (c) doc b , alkenes structure and naming (c) doc b

The molecular structure and naming of alkenes

Interpreting the fragmentation pattern of the mass spectrum of 2-methylbut-1-ene

[M]+ is the molecular ion peak (M) with an m/z of 70 corresponding to [C5H10]+, the original 2-methylbut-1-ene molecule minus an electron, [H2C=C(CH3)CH2CH3]+

The small M+1 peak at m/z 71, corresponds to an ionised 2-methylbut-1-ene molecule with one 13C atom in it i.e. an ionised 2-methylbut-1-ene molecule of formula [13C12C4H10]+

Identifying the species giving the most prominent peaks (apart from M) in the fragmentation pattern of 2-methylbut-1-ene.

The most abundant ion of the molecule under mass spectrometry investigation (2-methylbut-1-ene) is usually given an arbitrary abundance value of 100, called the base ion peak, and all other abundances ('intensities') are measured against it.

The base peak ion for the mass spectrum of 2-methylbut-1-ene is the m/z 55 ion [C4H7]+

The parent molecular ion is m/z of 70 corresponding to [C5H10]+  or   [H2C=C(CH3)CH2CH3]+

m/z value of [fragment]+ 70 56 55  [C4H7]+ 53 42
[molecular fragment]+ [C5H10]+ [C4H8]+ [H2C=C(CH3)CH2]+ [C4H5]+ [C3H6]+
m/z value of [fragment]+ 41 39 29 27
[molecular fragment]+ [C3H5]+ [C3H3]+ [CH3CH2]+ [C2H3]+

Analysing and explaining the principal ions in the fragmentation pattern of the mass spectrum of 2-methylbut-1-ene

PLEASE NOTE I have found it difficult to find 'authentic' equations to explain mass spectra fragmentation patterns and it is complex chemistry! I've identified the formulae of the ionised fragments on the mass spectrum diagram, but the equations are from the internet or my conjecture as to how the ions might be formed - please take care in using the information, especially for assignments at university or pre-university level.

Suggested equations to explain some of the most abundant ion peaks of 2-methylbut-1-ene

Formation of m/z 55 ion:

[H2C=C(CH3)CH2CH3]+  ===>  [H2C=C(CH3)CH2]+  +  CH3

The m/z 55 ion is the base peak ion, the most abundant and 'stable' ion fragment.

Formed by C-C bond scission and loss of methyl group.

mass change 70 - 15 = 55 (M-15 ion).

The m/z 55 ion can lose hydrogen atoms to give the m/z 54 or 53 ion.

Note the m/z peak of 56 could correspond with the ion [13C12C3H7]+ rather than the ion [C4H8]+, and formed in the same way as the m/z 55 ion.

An accurate mass spectrometer sorts this out, measuring relative fragment ion masses to four decimal places e.g. using very accurate relative isotopic masses,

12C = 12.0000  13C = 13.0034, 1H = 1.0078, you can then calculate (predict) that the accurate relative ion masses are:

For m/z 56: [13C12C3H7]+ = 56.0580, [C4H8]+ = 56.0624, a difference of 0.0044 in relative ion mass.

Formation of m/z 42 ion

[H2C=C(CH3)CH2CH3]+  ===>  [C3H6]+  +  CH2=CH2

Formed by C-C bond scission. proton migration, and loss of non-ionised ethene molecule.

mass change 70 - 28 = 42 (M-28 ion)

The m/z 42 ion can lose hydrogen atoms to give the m/z 41 or 39 ions.

Formation of m/z 41 ion

[H2C=C(CH3)CH2CH3]+  ===>  [C3H5]+  +  CH2CH3

Formed by C-C bond scission and loss of non-ionised ethyl group

mass change 70 - 29 = 41 (M-29 ion)

Formation of m/z 39 ion

 [C3H5]+  ===>  [C3H3]+  +  H2

Formation of m/z 29 ion

[H2C=C(CH3)CH2CH3]+  ===>  [CH2CH3]+  +  C3H5

Formed by C-C bond scission and loss of ionised ethyl group.

mass change 70 - 41 = 29 (M-41 ion).

The m/z 29 ion can lose hydrogen atoms to give the m/z 27 ion.


alkenes structure and naming (c) doc bSummary of key points for the mass spectrum of 2-methylbut-1-ene plus extra exam revision comments

A structured breakdown of the mass spectrum of 2-methylbut-1-ene, tailored for advanced A-level and IB Chemistry exam boards. This includes key fragment ions, misconceptions, and revision strategies.


Overview of 2-Methylbut-1-ene

  • Molecular formula: C5H10
  • Molecular ion (M⁺): m/z = 70
  • Structure: CH2=C(CH3)CH2CH3
  • Functional groups: Terminal alkene, methyl and ethyl substituents

Prominent Fragment Ions in the mass spectrum of 2-methylbut-1-ene

m/z Ion Formula Fragment Origin Notes
70 C5H10+ Molecular ion (M⁺) May be weak or absent
55 C4H7+ Loss of CH3 (–15) Allylic or alkyl fragment, base peak ion
41 C3H5+ Allyl cation Common in alkenes, m/z 39 and 42 ions also quite prominent
29 C2H5+ Ethyl fragment Stable alkyl ion
27 C2H3+ Vinyl cation Indicates unsaturation
15 CH3+ Methyl fragment Often intense

Common Misconceptions about the mass spectrum of 2-methylbut-1-enersus (see also below)

  • Assuming M⁺ is always the tallest peak: The base peak is often a stable fragment, not the molecular ion.
  • Confusing alkyl fragments: C2H5⁺ (m/z 29) v C3H5⁺ (m/z 41) — both common but arise from different cleavages.
  • Overinterpreting low m/z peaks: Peaks like m/z 15 (CH3⁺) are ubiquitous and not diagnostic alone.
  • Ignoring rearrangements: Allylic rearrangements can lead to unexpected fragment ions.

Exam Revision Tips for questions involving the mass spectrum of 2-methylbut-1-ene (AQA, Edexcel, OCR, WJEC, CCEA, CIE, IB) (see also above)

Molecular Ion Identification

  • Look for M⁺ peak at m/z 70 — confirms molecular mass.
  • If absent, use base peak and known fragments to deduce structure.

Fragmentation Logic

  • Practice predicting fragment ions by breaking C–C bonds near functional groups.
  • Use mass differences to deduce lost groups (e.g. 70 → 55 = loss of CH₃).

Isomer Comparison

  • Compare spectra of 2-methylbut-1-ene versus 2-methylbut-2-ene:
    • Different fragmentation due to position of double bond.
    • Allylic versus vinylic cleavage patterns.

Integration with IR/NMR

  • Use mass spec to confirm molecular formula.
  • Combine with IR for functional group and NMR for structural detail.

Data Sheet Familiarity

  • Know common m/z values for alkyl and unsaturated fragments.
  • Practice annotating spectra with fragment origins.

alkenes structure and naming (c) doc bPractice questions based on the mass spectrum of 2-methylbut-1-ene

Three varied, technically sound multiple-choice questions on the mass spectrum of 2-methylbut-1-ene (C5H10), designed for advanced pre-university chemistry students across AQA, Edexcel, OCR, WJEC, CCEA, CIE, IB, and US AP/Honors curricula.

These questions explore fragmentation logic, isotopic neutrality, and structural comparison with isomers — not just ion identification.


Question 1: Fragmentation Pathway and Base Peak based on the mass spectrum of 2-methylbut-1-ene

In the mass spectrum of 2-methylbut-1-ene, the base peak appears at m/z 41.

Which of the following best explains the formation of this fragment?

  1. Loss of a methyl radical to form a primary carbocation
  2. Cleavage of the double bond to form an allyl cation
  3. Formation of a tert-butyl cation after rearrangement
  4. Loss of ethene to form a stable acylium ion

Correct Answer: B

Explanation:

  • 2-methylbut-1-ene contains a terminal alkene and a branched methyl group
  • Fragmentation often yields the allyl cation (CH2=CH–CH2⁺), which is resonance-stabilized
  • Allyl cation has m/z 41, and is commonly the base peak in alkenes due to its stability

Distractor Analysis:

Option Why It’s Incorrect
A Primary carbocations are less stable and typically appear at m/z 43 or lower
C No tert-butyl group is present in the structure
D Acylium ions are characteristic of carbonyl compounds, not alkenes

Question 2: Isotopic Pattern Recognition based on the mass spectrum of 2-methylbut-1-ene

Why does the molecular ion peak of 2-methylbut-1-ene appear as a single peak rather than a close cluster of isotopic peaks?

  1. The molecule contains only carbon and hydrogen, which have negligible isotope effects in mass spectrometry
  2. The molecule contains oxygen, which has only one stable isotope
  3. The molecule contains chlorine, but its isotopes are not detected in mass spectrometry
  4. The molecule contains bromine, which produces a 1:1 isotope pattern that overlaps

Correct Answer: A

Explanation:

  • 2-methylbut-1-ene contains only C and H atoms
  • ¹³C and ²H exist but are low in abundance, so the M+1 peak is weak
  • No halogens or elements with strong isotope patterns are present, so the molecular ion appears as a single peak

Distractor Analysis:

Option Why It’s Incorrect
B Oxygen is not present in this molecule
C Chlorine is not present; if it were, it would produce a 3:1 M/M+2 pattern
D Bromine is not present; it would produce a 1:1 M/M+2 pattern if it were

Question 3: Isomer Differentiation by Fragmentation based on the mass spectrum of 2-methylbut-1-ene

Which of the following best explains why the mass spectrum of 2-methylbut-1-ene differs from that of pent-1-ene, even though both have the same molecular formula (C5H10)?

  1. 2-methylbut-1-ene has a higher molecular ion peak due to its branched structure
  2. Pent-1-ene contains a chlorine atom, which alters its fragmentation pattern
  3. 2-methylbut-1-ene forms a more stable allyl cation, leading to a stronger base peak at m/z 41
  4. Pent-1-ene undergoes rearrangement to form a tertiary carbocation, while 2-methylbut-1-ene does not

Correct Answer: C

Explanation:

  • Both molecules have the same molecular ion (m/z 70), but fragment differently
  • 2-methylbut-1-ene fragments to form a resonance-stabilized allyl cation (m/z 41)
  • Pent-1-ene tends to form primary or secondary carbocations, which are less stable
  • This leads to different base peaks in their spectra

Distractor Analysis:

Option Why It’s Incorrect
A Branching does not change the molecular ion mass
B Neither molecule contains chlorine
D Pent-1-ene does not readily form tertiary carbocations due to its linear structure

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Links associated with 2-methylbut-1-ene

The Infrared spectrum of 2-methylbut-1ene

The H-1 NMR spectrum of 2-methylbut-1ene

The C-13 NMR spectrum of 2-methylbut-1ene

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