- Given the neutralisation equation:
**NaOH**? [vct-1]_{(aq)}+ HCl_{(aq)}==> NaCl_{(aq)}+ H_{2}O_{(l)}

25 cm^{3}of hydrochloric acid are neutralised by 20 cm^{3}of 0.05M sodium hydroxide. What is the molarity of the acid- 0.04
- 0.02
- 1.25
- 0.80

- Given the neutralisation equation:
**NaOH**? [vct-2]_{(aq)}+ HCl_{(aq)}==> NaCl_{(aq)}+ H_{2}O_{(l)}

15 cm^{3}of hydrochloric acid are neutralised by 25 cm^{3}of 0.06M sodium hydroxide. What is the molarity of the acid- 0.40
- 0.10
- 0.04
- 0.01

- Given the neutralisation equation:
**NaOH**? [vct-3]_{(aq)}+ HCl_{(aq)}==> NaCl_{(aq)}+ H_{2}O_{(l)}

40 cm^{3}of 0.05M hydrochloric acid are neutralised by 20 cm^{3}of a sodium hydroxide solution. What is the molarity of the alkali- 0.20
- 0.05
- 0.10
- 0.50

- Given the neutralisation equation:
**NaOH**? [vct-4]_{(aq)}+ HCl_{(aq)}==> NaCl_{(aq)}+ H_{2}O_{(l)}

25 cm^{3}of 0.16M hydrochloric acid are neutralised by 10 cm^{3}of a sodium hydroxide solution. What is the molarity of the alkali- 0.2
- 0.1
- 0.8
- 0.4

- Given the neutralisation equation:
**2KOH**? [vct-5]_{(aq)}+ H_{2}SO_{4(aq)}==> K_{2}SO_{4(aq)}+ 2H_{2}O_{(l)}

What is the molarity of a sulphuric acid solution, if 15 cm^{3}of it are neutralised by 20 cm^{3}of a 0.3 M potassium hydroxide solution- 0.20
- 0.15
- 0.40
- 0.75

- Given the neutralisation equation:
**2KOH**? [vct-6]_{(aq)}+ H_{2}SO_{4(aq)}==> K_{2}SO_{4(aq)}+ 2H_{2}O_{(l)}

What is the molarity of a sulphuric acid solution, if 30 cm^{3}of it are neutralised by 10 cm^{3}of a 0.6 M potassium hydroxide solution- 0.20
- 0.10
- 0.05
- 0.25

- Given the neutralisation equation:
**2KOH**? [vct-7]_{(aq)}+ H_{2}SO_{4(aq)}==> K_{2}SO_{4(aq)}+2H_{2}O_{(l)}

What is the molarity of a potassium hydroxide solution, if 10 cm^{3}of it are neutralised by 12 cm^{3}of a 0.5 M sulphuric acid solution- 2.4
- 0.6
- 1.2
- 0.6

- Given the neutralisation equation:
**2KOH**? [vct-8]_{(aq)}+ H_{2}SO_{4(aq)}==> K_{2}SO_{4(aq)}+ 2H_{2}O_{(l)}

What is the molarity of a potassium hydroxide solution, if 5 cm^{3}of it are neutralised by 20 cm^{3}of a 1 M sulphuric acid solution- 16
- 4
- 5
- 8

- Given the neutralisation equation:
**3NaOH**? [vct-9]_{(aq)}+ H_{3}PO_{4(aq)}==> Na_{3}PO_{4(aq)}+ 3H_{2}O_{(l)}

What is the molarity of a phosphoric acid solution, if 15 cm^{3}of it are neutralised by 22.5 cm^{3}of a 0.2 M sodium hydroxide solution- 0.10
- 0.30
- 0.03
- 0.01

- Given the neutralisation equation:
**3NaOH**? [vct-10]_{(aq)}+ H_{3}PO_{4(aq)}==> Na_{3}PO_{4(aq)}+ 3H_{2}O_{(l)}

What is the molarity of a phosphoric acid solution, if 40 cm^{3}of it are neutralised by 15 cm^{3}of a 0.4 M sodium hydroxide solution- 0.150
- 0.050
- 0.017
- 0.115

- Given the neutralisation equation:
**3NaOH**? [vct-11]_{(aq)}+ H_{3}PO_{4(aq)}==> Na_{3}PO_{4(aq)}+ 3H_{2}O_{(l)}

What is the molarity of a sodium hydroxide solution, if 21.6 cm^{3}of it are neutralised by 18 cm^{3}of a 0.2 M phosphoric acid solution- 1.50
- 1.15
- 0.50
- 0.17

- Given the neutralisation equation:
**3NaOH**? [vct-12]_{(aq)}+ H_{3}PO_{4(aq)}==> Na_{3}PO_{4(aq)}+ 3H_{2}O_{(l)}

What is the molarity of a sodium hydroxide solution, if 15 cm^{3}of it are neutralised by 20 cm^{3}of a 0.6 M phosphoric acid solution- 1.2
- 7.2
- 0.8
- 2.4